A square is drawn with the length of side equal to the diagonal of a cube. If the area of the square is `72075 cm^(2)`, then find the side of the cube.
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The ends of a diagonal of a square are `(2,-3)` and `(-1,1)dot` Another vertex of the square can be `(-3/2,-5/2)` (b) `(5/2,1/2)` `(1/2,5/2)` (d) none
Correct Answer - A::B For square ABCD, the vetices of diagonal AD, (2,-3) and D(-1,1), are given
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Frame the formula for the area (A) of a quadrilateral given by half the product of its diagonal (d) and sum of offsets drawn to the diagonal from its
Correct Answer - `A=(1)/(2)d(h_(1)+h_(2))`
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The diagonal of a rectangle is 10 units. The formula to find the diagonal is `d=sqrt(l^(2)+b^(2))`. Where l and b are length and breadth respectively.
Correct Answer - `l^(2)`
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The diagonals of a rhombus are 10 cm and 8 cm. If the area of rhombus is equal to `(1)/(10)th` of the area of a square, then find the cost of fencing
Correct Answer - Rs. 8
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The area of rhombus is `480 cm^2`, and one of its diagonal measures `48 cm`. Find the (i) length of the other diagonal (ii) the length of each of its
Correct Answer - `(i) 20 cm (ii) 26 cm (iii) 104 cm `
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In a four sider- field , the length of the longer diagonal is 128 m. the lengths of perpendiculars from the opposite vertices upon this diagonal are 2
Correct Answer - `2560 m^(2)`
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The sides of a rectangle are given by the equations x=-2, x = 4, y=-2 andy=5. Find the equation of the circle drawn on the diagonal of this rectangle
Correct Answer - ` x ^(2) + y ^(2) - 2x - 3y - 18 =0`
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Each side of a rhombus is 10 cm long and one of its diagonals measures 16 cm. Find the length of the other diagonal and hence find the area of the rho
Correct Answer - 12 cm, 96 `cm^(2)`
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The area of a rhombus is 480 `cm^(2)`, and one of its diagonals measures 48 cm. Find (i) the length of the other diagonal, (ii) the length of each of
Correct Answer - (i) 20 cm (ii) 26 cm (iii) 104 cm
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The perimeter of rectangle is 34cm and length of its diagonal is 13cm. Find the length and breadth of rectangle
let length of the rectangle be L and breadth be B so by the problem perimeter 2(IL+B)=34 => L+B =17 .......(1) => L2+B2+2LB=289 ..........(2) and the square of the diagonal = L2+B2=132 =169 .....(.3) By...
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