Two sides of a triangular field are 85 m and 154 m in length and its perimeter is 324 m. Find (i) the area of the field and (ii) the length of the perpendicular from the opposite vertex on the side measuring 154 m.
Given perimeter of square field is 8 km
let 'a' be its side
then perimeter = 4a = 8km
[a = 2km]
we know 1 hectares =0.01(km)2
area of filed = a2
= 4km2
then area of hectare = 400/0.01 =...
Correct option is (D) \(\frac{7}{2}\)
Let radius of the sphere is r cm.
\(\therefore\) \(4\pi r^2\) = 154 \((\because\) Surface area of sphere \(=4\pi r^2)\)
\(r^2=\frac{154}{4\pi}=\frac{154\times7}{4\times22}=\frac{7\times7}4=\frac{7^2}{2^2}=(\frac72)^2\)
\(\therefore\) \(r=\frac72\)
Hence, radius of sphere is \(\frac72\,cm\)