If the perimeter of a rectangle is 10 cm and the difference between its length and breadth is 1 cm, then its length is ______ and its breadth is ______.
Correct Answer - D
Since ABCD is a rectangle, `(AC)^2=(AB)^2+(BC)^2`
`=(AB)^2[1+(9)/(16)]=(25)/(16)(AB)^2`
and `PA=(AC)/(2)=(5AB)/(8)`
`(5)/(8)sqrt((-1-3)^2+(2-7)^2)=5(sqrt41)/(8)`
let length of the rectangle be L and breadth be B
so by the problem perimeter 2(IL+B)=34
=> L+B =17 .......(1)
=> L2+B2+2LB=289 ..........(2)
and the square of the diagonal = L2+B2=132 =169 .....(.3)
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