Escape velocity on a planet is ve. If radius of the planet remains same and mass becomes 4 times, the escape velocity becomes
(A) 4ve
(B) 2ve
(C) ve
(D) 0.5 ve
Correct Answer - `30^(@), 0.866AU`
2 Answers 3 viewsCorrect option is: (A) T Period of resolution \(T = 2 \pi \sqrt \frac{R^3}{GM} \) \(T = 2 \pi \sqrt \frac{R^3}{G \frac{4}{3} \pi R^3 \rho} \) The period of revolution depends upon the density of...
2 Answers 1 viewsCorrect option is: (B) \(2v_e\) Escape Velocity \(v_e = \sqrt {2gRe}\) \(\frac{V_{e1}}{V_{e2}} \propto \sqrt \frac{4R_1}{R_1}\) \(V_{escape \ 2} = 2 \ V_{escape \ 1}\)
2 Answers 1 viewsCorrect option is: (A) 11.2 km/s Escape velocity does not depend on the angle of projection. \(V_{escape} = \sqrt {2gRe} \)
2 Answers 1 viewsCorrect option is: (B) \(\sqrt{2}\)vo = ve
2 Answers 2 viewsCorrect Answer - (i) 0.28 (ii) 0.4 (iii) 0.32
2 Answers 1 viewsCorrect answer is (b) We know that \(\tau\) = r × F ∵ \(\tau\) \(= \frac{dL}{dt},\) \(F = \frac{dP}{dt}\) \(\left(\frac{dL}{dt}\right) = r \times \left(\frac{dP}{dt}\right)\) \(\left(\frac{dL}{dt}\right) - r \times \left(\frac{dP}{dt}\right) = 0\)
2 Answers 1 viewsGiven that \(\vec a, \vec b\) and \(\vec c\)are unit vectors. i.e., |\(\vec a\)| = |\(\vec b\)| = |\(\vec c\)| = 1 And \(\vec a\) + \(\vec b\) + \(\vec c\) = \(\vec 0\) Then \((\vec a+\vec b+\vec c).(\vec a+\vec b+\vec c)=\vec 0.\vec...
2 Answers 1 views