Escape velocity on a planet is ve. If radius of the planet remains same and mass becomes 4 times, the escape velocity becomes

(A) 4ve

(B) 2ve

(C) ve

(D) 0.5 ve


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Call

Correct option is: (B) \(2v_e\)

Escape Velocity

\(v_e = \sqrt {2gRe}\)

\(\frac{V_{e1}}{V_{e2}} \propto \sqrt \frac{4R_1}{R_1}\)

\(V_{escape \ 2} = 2 \ V_{escape \ 1}\)

Call

Correct option is: (B) 2ve