निम्नलिखित के हरो का परिमेयकरण कीजिए : (i) `(1)/(sqrt(7))` `(ii) (1)/(sqrt(7)-sqrt(6))` (iii) `(1)/(sqrt(5)+sqrt(2))` (iv) `(1)/(sqrt(7)-2)`
Answered Feb 05, 2023
Correct Answer - (i) `(sqrt(7))/(7)" "` (ii) `sqrt(7)+sqrt(6) " " ` (iii) `(sqrt(5)-sqrt(2))/(3) " " ` (iv) ` (sqrt(7)+2)/(3)`
Correct Answer - `+-sqrtsin2theta`
Correct Answer - `(i) (5,oo)` `(ii) (5,7]` `(iii) R` `(iv) x in phi` `(v)(-oo,2)uu(8,oo)` `(vi) (-oo,-2)` `(vii) x in (0,(1)/(3)]` `(viii) x in (-oo,-4)uu[(1)/(2),(8)/(7)]`
Correct Answer - (i) 9.898 (ii) 17.32 (iii) 18.24 (iv) 6.928
Correct Answer - (i) 1 (ii) 1
Correct Answer - `-0.891`
Correct Answer - (i) 2 (ii) 3 (iii) 4 (iv) 6
Correct Answer - (i)`sqrt(2)` (ii)`(1)/(sqrt(3))` (iii)`(sqrt(3))/(2)` (iv)`3sqrt(2)` (v)`(1)/(2sqrt(5))` (vi)`2sqrt(2)`
Correct Answer - (i)`sqrt(3)` (ii)`(1)/(sqrt(2))` (iii)`(5)/(3)` (iv)`(3)/(4)`
Correct Answer - (i),(iv) और (v) अपरिमेय है ; (ii) और (iii) परिमेय है ।
Correct Answer - (i) `6+3sqrt(2) +2sqrt(3)+sqrt(6)" "`(ii) 6`" "` (iii) `7+2sqrt(10) " "` (iv) 3
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