The time period of revolution of moon around the earth is 28 days and radius of its orbit is `4xx10^(5)` km. If `G=6.67xx10^(-11) Nm^(2)//kg^(2)` then find the mass of the earth.
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The magnetic dipole moment of earth is `6*4xx10^(21)Am^2`. If we consider it to be due to a current loop wound around the magnetic equator of the eart
Correct Answer - ` 5 xx 10^(7) A`
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The distance of Venus form the sun as determine by radar echo method is found to be `1.082xx10^(11)m`. The period of its revolution is 224.633 days. I
Correct Answer - `1.494xx10^(11)m`
2 Answers 1 views
Phobo is a satellite of Mars. The period of its revolution around Mars is 0.319 days and its mean distance from Mars is `9.519xx10^(6)m`. Assuming tha
Correct Answer - `5.677xx10^(24)kg`
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What is the solid angle subtended by the moon at any point of the Earth, given the diameter of the moon is 3474 km and its distance
Given: Diameter (D) = 3474 km ∴ Radius of moon (R) = 1737 km = 1.737 × 106 m Distance from Earth r = 3.84 × 108 m To find: Solid angle (dΩ) Formula: dΩ = \(\frac{dA}{r^2}\) Calculation: From formula, dΩ...
2 Answers 2 views
Vianay and Vikram can complete a work in 48 and 36 days, respectively . If they work on alternate days beginning with Vinay, in how many days will the
Correct Answer - `41(1)/(4)`
2 Answers 2 views
Prakash, Rohit and Sameer cam complete a job in 1 days, 20 days, adn 10 days, respectively. They sarted the job but Prakash was unwell on the first da
Correct Answer - `15%`
2 Answers 3 views
Prakash, Ramesh and Suresh started a job. After 2 days, Prakash left. After another 2 days, Ramesh left. In another 2 days. Suresh completed the reami
Correct Answer - Suresh
2 Answers 1 views
A planet is revolving around a star in a circular orbit of radius R with a period T. If the gravitational force between the planet and the star
Correct option is: (A) T2 ∝ R5/2
2 Answers 1 views
Time period of revolution of a satellite around a planet of radius R is T. Period of revolution around another planet whose radius is 3R is
Correct option is: (A) T Period of resolution \(T = 2 \pi \sqrt \frac{R^3}{GM} \) \(T = 2 \pi \sqrt \frac{R^3}{G \frac{4}{3} \pi R^3 \rho} \) The period of revolution depends upon the density of...
2 Answers 1 views