Prakash, Ramesh and Suresh started a job. After 2 days, Prakash left. After another 2 days, Ramesh left. In another 2 days. Suresh completed the reaminin part of the job . If Prakash can complete the same work in more than 6 days, and Ramesh can complete it in more than 12 days, who got the highest share of the wages?
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Satish, Goel and Khan can do a particular job in 24,36 and 48 days respectively. If they start working together and are paid ₹ 5200 for their work, th
Correct Answer - ₹ 2400,₹ 1600,₹ 1200
2 Answers 2 views
Ramesh bought 30 Rs.200 shares of a company available at a - premium of Rs.25. Find the investment made by Ramesh, and also the rate of interest (retu
Correct Answer - Rs.6750; `7.11%`
2 Answers 1 views
Anil bought a cycle for ₹ 1500 and sold it to Ramesh at a profit of 10%. Satish bought the cycle from Ramesh for a certain price which resulted in a l
Correct Answer - ₹1600
2 Answers 1 views
Vianay and Vikram can complete a work in 48 and 36 days, respectively . If they work on alternate days beginning with Vinay, in how many days will the
Correct Answer - `41(1)/(4)`
2 Answers 2 views
Prakash, Rohit and Sameer cam complete a job in 1 days, 20 days, adn 10 days, respectively. They sarted the job but Prakash was unwell on the first da
Correct Answer - `15%`
2 Answers 3 views
4. The value of \( \left(\frac{1}{2}\right)^{-2}+\left(\frac{1}{3}\right)^{-2}+\left(\frac{1}{4}\right)^{-2} \) is (a) \( \frac{61}{144} \) (b) \( \frac{144}{61} \) (c) 29 (d) none of these
Correct answer is:- (c) 29 Explanation:- 1/2-2 + 1/3-2 + 1/4-2 = 22 + 32 + 42 (x-1 = 1/x) = 4 + 9 + 16 = 29
2 Answers 1 views
“Germany unification was not completed with speeches and functions” but it is completed only with blood & Iron policy was said by
Answer is (B) Bismark
2 Answers 1 views
Consider a particle of mass \( m \) having linear momentum \( P \) at position \( r \) relative to the origin \( O \). Which of the following equations correctly relates \( r , P , L \) ? a) \( \left[\left(\frac{d L}{d t}\right)+r x\left(\frac{d P}{d t}\right)\right]=0 \) b) \( \left[\left(\frac{d L}{d t}\right)-r x\left(\frac{d P}{d t}\right)\right]=0 \) c) \( \left[\left(\frac{d L}{d t}\right) \times\left(\frac{d r}{d t}\right) \times P\right]=0 \) d) \( \left[\left(\frac{d L}{d t}\right)-\left(\frac{d r}{d t}\right) \times P\right]=0 \)
Correct answer is (b) We know that \(\tau\) = r × F ∵ \(\tau\) \(= \frac{dL}{dt},\) \(F = \frac{dP}{dt}\) \(\left(\frac{dL}{dt}\right) = r \times \left(\frac{dP}{dt}\right)\) \(\left(\frac{dL}{dt}\right) - r \times \left(\frac{dP}{dt}\right) = 0\)
2 Answers 1 views
I) Prakash blood didn’t show clumping with antiA antibodies. II) Hasith’s blood clumped with only anti-A antibodies.
D) Prakash is B positive and Hasith is A positive
2 Answers 1 views