On the basis of even-odd of protons and neutrons, what type of nuclides are most stable ?

Correct Answer - A::B::C We have `(x+a)^(n) = .^(n)C_(0)x^(n)+.^(n)C_(1)x^(n-1)a+.^(n)C_(2)x^(n-2)a^(2) + "....." + .^(n)C_(n)a^(n)` `= [.^(n)C_(0)x^(n)+.^(n)C_(2)x^(n-2)+"..."]+[.^(n)C_(1)x^(n-1)a+.^(n)C_(3)x^(m-3)a^(3)+"...."]` or `(x+a)^(n) = P+Q" "(1)` Similarly `(x-a)^(n) = P - Q" "(2)` (i) `(1) xx (2)...

Correct Answer - (b) A=228

The nuclides with odd number of both protons and neutrons are the least stable because, odd number of protons and neutrons results in the presence of two unpaired nucleons. These unpaired...

Beta decay occurs when an unstable nucleus emits a beta particle and energy. A beta particle is either an electron or a positron. An electron is a negatively charged particle,...

Isotopes : \(_{17}^{38}Cl\) and \(_{17}^{35}Cl\) Isobars : \(_6^{14}C\) and \(_{7}^{14}N\) Isotones : i. \(_1^3H\) and \(_2^4He\) ii. \(_{16}^{32}S\) and \(_{15}^{31}P\) 

The representation of the given element is \(_6^{14}X\).

For the given nuclide, Atomic number, Z = 18,  Mass number, A = 40  Number of protons = Number of electrons = Z = 18 Number of neutrons (N) = A – Z = 40...

i. \(_8^{17}O\)  Atomic number, Z = 8,  Mass number, A = 17  Number of protons = Number of electrons = Z = 8 Number of neutrons (N) = A – Z = 17 – 8...

Correct Option is : (C) 18, 15, 16 Atomic Number = Number of Protons Mass Number = Number of Protons + Number of Neutrons Number of Electron = Atomic Number -(Number of Charges) Therefore, Number of...