If the three elements X,Y and Z form a triad and atomic weights of X and Z are 9 and 40 respectively then the atomic weight of an element y is _________
Given :
n(X)=6
n(y)=5
n(z)=4
Also,the elements are distinct
Therefore,these three are disjoint sets
==>n(X∩Z) =0 -------- (1)
Now,her
S=(X-Y)∪Z=X∪Z [Because X∩Z=∅==>X-Z=X]
==>n(S)=n(X∪Z)
==>n(S)=n(X)+n(Z)-n(X∩Z)
==>n(S)=n(X)+n(Z)-0 [From (1)]
==>n(S)=6+4=10
Therefore,
Number of proper subsets of S=2n(S)-1
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