Given :
n(X)=6
n(y)=5
n(z)=4
Also,the elements are distinct
Therefore,these three are disjoint sets
==>n(X∩Z) =0 -------- (1)
Now,her
S=(X-Y)∪Z=X∪Z [Because X∩Z=∅==>X-Z=X]
==>n(S)=n(X∪Z)
==>n(S)=n(X)+n(Z)-n(X∩Z)
==>n(S)=n(X)+n(Z)-0 [From (1)]
==>n(S)=6+4=10
Therefore,
Number of proper subsets of S=2n(S)-1
...
The subshell in which the last electron enters decides the block to which an element belongs.
In group 1 and group 2 elements, the last electron is filled in the s...
Sr. no.
Property
Down a group
i
Atomic radii
Increases
ii
Ionic radii
Increases
iii
Ionization enthalpy
Decreases
iv
Electronegativity
Decreases
v
Standard reduction potential
Decreases