The price of a refrigetor, P is 5 times that of a cooler Q. If then price of P increases by `40%.` then what is the change in the total price of the refrigerator and cooler put together ?
Probability of success is 3/6=1/2. `thereforep=1/2andq=1/2` (i) For exactly 4 successes, the required probability is `""^(7)C_(4)((1)/(2))^(4)((1)/(2))^(3)=35/128` (ii) For at least 4 successes, the required probability is `""^(7)C_(4)((1)/(4))^(4)((1)/(2))^(3)+""^(7)C_(5)((1)/(2))^(5)((1)/(2))^(2)` `+""^(7)C_(6)((1)/(2))^(6)((1)/(2))^(1)+""^(7)C_(7)((1)/(2))^(7)` `=35/128+21/128+7/128+1/128=64/128=1/2`
2 Answers 1 viewsCorrect Answer - `n=14` According to question `""^(n)C_(6)((1)/(2))^(6)((1)/(2))^(n-6)=""^(n)C_(8)((1)/(2))^(8)((1)/(2))^(n-8)` `or ""^(n)C_(6)((1)/(2))^(n)=""^(n)C_(8)((1)/(2))^(n)` `or""^(n)C_(6)=""^(n)C_(8)=""^(n)C_(n-8)` `implies6=n-8orn=14`
2 Answers 1 viewsCorrect Answer - D According to the givn condition, `""^(n)C_(3)((1)/(2))^(n)=""^(n)C_(4)((1)/(2))^(n),` where n is the number of times die is thrown. `therefore""^(n)C_(3)=""^(n)C_(4)impliesn=7` Thus, the required probability is `=""^(7)C_(1)((1)/(2))^(7)=(7)/(2^(7))=(7)/(128)`
2 Answers 1 viewsCorrect Answer - C The required probability is 1- probability of getting equal number of heads and tails `=1-""^(2n)C_(n)((1)/(2))^(n)((1)/(2))^(2n-n)` `=1-((2n)!)/((n!)^(2))xx(1)/(4^(n))`
2 Answers 1 viewsCorrect Answer - [Decreased to 50% of initial value]
2 Answers 1 viewsCorrect Answer - `(63)/(100)`
2 Answers 1 viewsC) Simla is in higher altitude
2 Answers 1 viewsCorrect Answer - (i) 0.57 (ii) 0.43
2 Answers 1 viewsCorrect Answer - (i) 0.28 (ii) 0.4 (iii) 0.32
2 Answers 1 viewsCorrect answer is (b) We know that \(\tau\) = r × F ∵ \(\tau\) \(= \frac{dL}{dt},\) \(F = \frac{dP}{dt}\) \(\left(\frac{dL}{dt}\right) = r \times \left(\frac{dP}{dt}\right)\) \(\left(\frac{dL}{dt}\right) - r \times \left(\frac{dP}{dt}\right) = 0\)
2 Answers 1 views