A balloon is inflated with helium gas at room temperature of 25 °C and at 1 bar pressure when its initial volume is 2.27L and allowed to rise in air.

Monjur Alahi

A balloon is inflated with helium gas at room temperature of 25 °C and at 1 bar pressure when its initial volume is 2.27L and allowed to rise in air. As it rises in the air external pressure decreases and the volume of the gas increases till finally it bursts when external pressure is 0.3bar. What is the limit at which volume of the balloon can stay inflated ?


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Salim Ahmed Kawsar

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Given : 

P1 = Initial pressure = 1 bar 

V1 = Initial volume = 2.27 L 

P2 = Final pressure = 0.3 bar 

To find :

V2 = Final volume 

Formula : 

P1V1 = P2V2 (at constant n and T) 

Calculation :

According to Boyle’s law,

P1V1 = P2V2 (at constant n and T) 

∴ V2 = \(\frac{P_1V_1}{P_2}\)

= \(\frac{1\times 2.27}{0.3}\) 

= 7.566667 L ≈ 7.567 L

∴ The balloon can stay inflated below the volume of 7.567 L.

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