Explain :
Sodium dissolves in liquid ammonia to form a solution which shows electrical conductivity.
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Sodium bicarbonate on heating decomposes to form sodium carbonate, `CO_(2)`, and water. If 0.2 mole of sodium bicarbonate is completely decomposed, ho
Correct Answer - A The reaction is involved is: `2NaHCO_(3)(s) overset(Delta)to Na_(2)CO_(3)(s)+CO_(2)(g)+H_(2)O(l)`
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The specific conductivity of 0.02 M KCl solution at `25^(@)C` is `2.768xx10^(-3) ohm^(-1) cm^(-1)`. The resistance of this solution at `25^(@)C` when
Cell constant `=("Sp. Cond. Of KCl")/("Conductance of KCl")` `=(2.768 xx 10^(-3))/(1//250.2)` `=2.768xx10^(-3)xx250.2` For 0.01 M `CuSO_(4)` solution Sp. Conductivity = Cell constant `xx` Conductance `=2.768xx10^(-3) xx250.2xx1/8331` Molar conductance =Sp. cond....
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(a). The resistance of a decinormal solution of an electrolyte in a conductivity cell was found to be 245 ohms. Calculate the equilvalet conductivity
Given `R=245Omega, N=(1)/(10),l=2cm, A =3.5cm^(2)` `lamda_(eq)^(infty)=390.5Scm^(2)mol^(-1)` Asked `lamda_(eq)and k_(a)=?` formula used `k=Gxx(l)/(a)=(1)/(R)xx(l)/(a).^^_(eq)=Kxx(1000)/("normality"),alpha=(^^_(m))/(^^_(m)^(@))` Explanation `k=` conductivity, `N=` normality `lamda_(eq)=` equivalence conductance `lamda_(eq)^(infty)=` equivalence conductance at infinite dilution. substitution ad calculation: (a)....
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Mole fraction of liquid A (M = 20) present with liquid B(M = 25) in a solution of A (l) and B (l) is 0.6, then weight of solution per 50 g of liquid B
Correct Answer - B `n_(A)=6 " mas of "A = 6xx20 =120 g` `n_(B)=4 " mas of "B = 4xx25 =100 g` `100 g " of "B = 220 g `...
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The conductivity of 0.001 `"mol" L^(-1)` solution of `CH_(3)COOH " is " 3.905 xx 10^(-5) "S" cm^(-1)`. Calculate its molar conductivity and degree of
`wedge_(m) = (K("conductivity") xx 1000)/(M)` `= (3.905 xx 10^(-5) xx 1000)/(0.001)` `=39.055 " cm"^(2)"mol"^(-1)` `=(wedge^(c)m)/(wedge^(@)m) = (39.05)/(wedge^(@)m) " " [wedge_(CH_(3)COOH)^(@) = wedge_(CH_(3)COO^(-))^(@) + wedge _(H)^(@)+` `= 349.6 + 6 +0.9`...
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Sodium gets dissolved in liquid ammonia because of ____________ .
Correct Answer - solvated electrons
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The resistance of 100m of copper wire of diameter `0.056 xx 10^(-2)` m is 6.62`Omega`. Calculate (i) resistivity, (ii) Electrical conductivity of copp
Correct Answer - (i) `1.63 xx 10^(-8)Omegam`
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How many total sodium ions are present in one formula uint of sodium ethane-1,2-diaminetetraacetatochromate (II) and sodium hexanitrito cobaltate (III
Correct Answer - `05`
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On which factors does the electrical conductivity of a pure semiconductor depend at a given temperature?
For pure semiconductor, the number density of free electrons and number density of holes is equal. Thus, at a given temperature, the conductivity of pure semiconductor depends on the number...
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3.40 g of ammonia at STP occupies volume of 4.48 dm^3. Calculate molar mass of ammonia.
Given : Mass of ammonia = 3.40 g Volume at STP = 4.48 dm3 To Find : Molar mass of ammonia Calculation : Let ‘x’ grams be the molar mass of NH3. Molar volume of a gas...
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