दिए गए वक्रो के लिए निर्दिष्ट बिन्दुओ पर स्पर्श रेखा के समीकरण ज्ञात कीजिए- `x=theta +sin theta , y=1 +cos theta, theta =pi/2 ` पर
Answered Feb 05, 2023
Correct Answer - `{:("स्पर्श रेखा", "अभिलम्ब"),(2x+2y-pi4=0, 2x-2y=pi):}`
Correct Answer - `[{:(,1,0),(,1,1):}]`
Correct Answer - `{:("स्पर्श रेखा", "अभिलम्ब"),(x/acps tjeta +y/b sin theta=1, ax sec theta -by cot theta=a^(2)-b^(2)):}`
Correct Answer - `{:("स्पर्श रेखा", "अभिलम्ब"),(x/asec theta-y/btan theta=1, ax cos theta + by cot theta=a^(2)+b^(2)):}`
Correct Answer - `{:("स्पर्श रेखा", "अभिलम्ब"),(x cos ^(3)theta +y sin ^(3)theta =c, x sin^(3) theta +2 c cot 2 theta =0):}`
Correct Answer - `{:("स्पर्श रेखा", "अभिलम्ब"),(13x-16y-2a=0, 16x+13y-9a=0):}`
Correct Answer - `{:("स्पर्श रेखा", "अभिलम्ब"),(x-y+a=0, x+y=3a):}`
Correct Answer - `{:("स्पर्श रेखा", "अभिलम्ब"),(bxsec t- ay tan t=ab, ax cos t +by cot t=a^(2)+b^(2)):}`
Correct Answer - `{:("स्पर्श रेखा", "अभिलम्ब"),(y=(x-a theta)tan (theta//2), (y-2a)tan (theta//2)+x- a theta =0):}`
Correct Answer - `{:("स्पर्श रेखा", "अभिलम्ब"),((sqrt2-1)x-y=2(sqrt2-1)-(pi)/(4),x+(sqrt2-1)y=(pi)/(4)(sqrt2-1)):}`
Correct Answer - `{:("स्पर्श रेखा", "अभिलम्ब"),(x+y-sqrt2=0,x=y):}`
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