सरल कीजिए, ` cos theta [{:( cos theta,, sin theta ), (-sin theta,, cos theta ):}] + sin theta [ {:(sin theta ,, - cos theta ), (cos theta ,, sin theta ):}]`
By defing A & B are equal if they have the same order and all the corresponding elements are equal.
Thus we have `sin theta=(1)/(sqrt2),c os theta=-(1)/(sqrt2)& tan theta=-1`
`Rightarrow...
We have,
`|A-lambdaI|=|(cos theta - lambda,-sin theta),(sin theta,cos theta - lambda)|`
`=(cos theta-lambda)^(2)+sin^(2) theta`
Therefore, characteristic equation of A is
`(cos theta-lambda)^(2)+sin^(2) theta=0`
or `cos theta-lambda= pm i sin theta`...
Correct Answer - C
`AB=[(cos^(2) theta,),(cos theta sin theta,)][(cos^(2) phi,cos phi sin phi),(cos phi sin phi,sin^(2) phi)]`
`=[(cos^(2) theta cos^(2) phi+cos theta cos phi sin theta sin phi ,cos^(2)theta cos phi...
Correct Answer - A::B::C
We have, `|A(theta)|=1`
Hence, A is invertiable.
`A(pi+theta)=A(pi + theta)=[(sin(pi+theta),i cos (pi+theta)),(i cos (pi+theta),sin (pi+theta))]`
`=[(-sin theta,-i co theta),(-i cos theta,-sin theta)]=-A(theta)`
adj `(A(theta))=[(sin theta,-i cos theta),(-i...