The temperature of a gas is `-68^(@)C`. To what temperature should it be heated so that (i) the average kinetic energy of the molecules be doubled and (ii) the root-mean-square velocity of the molecules be doubled ?
Correct Answer - B
We know that , `DeltaH=DeltaE+pDeltaV`
When, `DeltaV=0`
`therefore DeltaH=DeltaE`
In given problem `DeltaH=500 J `
`-W=-pDeltaV,DeltaV=0`
So, `DeltaE=q=500 J`
(i) 3.2 gram `CH_(4)`
number of moles `(CH_(4))=(w)/(M)=(3.2)/(16)=0.2` moles
(ii) 70 gram `N_(2)`
Number of moles `=(w)/(M)=(70)/(28)=2.5`
(iii) `4.5xx10^(24)` molecules of `O_(3)`
Number of moles `=("no. of molecules ")/(N_(A))=(4.5xx10^(24))/(6xx10^(23))=7.5`
(iv)...
Correct Answer - Energy of 1 mole of photon = `nxx (hC)/(lambda) = 6.023 xx 10^(23) xx (6.625 xx 10^(-34) xx 3 xx 10^(8))/(650 xx 10^(-9) xx 10^(3)) = 184...