When light of wavelength 400nm is incident on the cathode of photocell, the stopping potential recorded is 6V. If the wavelength of the incident light is to 600nm, calculate the new stopping potential. [Given `h=6.6xx10^(-34) Js, c=3xx10^(8)m//s , e=1.6xx10^(-19)C`]
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White light is incident normally on a glass plate (in air) of thickness `500 nm` and refractive index of `1.5`. The wavelength (in `nm`) in the visibl
Correct Answer - B For strong reflection. `2mut=(lambda)/(2),(3lambda)/(2),(5lambda)/(2).....rArr lambda=4mut,(4mut)/(3),(4mut)/(5),(4mut)/(7).....` `rArr 3000 nm. 1000 nm, 600 nm, 333 nm.` `rArr` only option is `600 nm`.
2 Answers 1 views
In a certain triode, the output is 5 mA with an anode potential of 200 V and grid potential `-3V`. When he potential is increased to 260 V, the curren
Correct Answer - `r_(p) = 20000 Omega, delta_(m) = 2xx 10^(-3) Omega^(-1),mu=40`
2 Answers 1 views
The distance between the two plates of a cathode-ray oscilloscope is 1 cm and the potential difference between them is 1200 V. If an electron of energ
Correct Answer - [0.34 cm]
2 Answers 1 views
In a cathode ray tube a potential difference of `3000` volt is maintained between the electrodes `2 cm` apart. A magnetic field of `2.5xx10^(-4) Wb//m
Correct Answer - `1.8 xx 10^(11) C kg^(-1)`
2 Answers 1 views
In an oil drop experiment, the following data were recorded : Plate separation = 15 mm, Distance of fall = 10 mm Potential difference = 3.2 kV, Viscos
Correct Answer - `4.8 xx 10^(-19) C, 3`
2 Answers 1 views
Photoelectric work function for a surface is 2.4 eV. Light of wavelength `6.8 xx 10^(-7)`m shines on the surface. Find the frequency of incident light
Correct Answer - `v =4.41 xx 10^(14)Hz,v_(0)=5.82 xx 10^(14) Hz`, no photoelectric emission occurs as `v lt v_(0)`
2 Answers 1 views
The cathode of a photocell is irradiated with light of wavelength `3000 Å`. The current through the cell is found to stop when the potential of the pl
Correct Answer - 2.04 eV
2 Answers 1 views
Given that a photon of light of wavelength 10,000Å has an energy equal to 1.23eV. When light of wavelength 5000Å and intensity `I_(0)` falls on a phot
Correct Answer - (i) 1.1 eV (ii) `1.6 xx 10^(-6) A` ; unchanged
2 Answers 1 views
The distance between the cathode (filament) and the target in an X-ray tube is 1.5 m. If the cutoff wavelength is 30 pm, find the electric field betwe
Correct Answer - `27.7 kV//m`
2 Answers 1 views
A well collimated parallel pencil of cathode rays falls through a potential difference `3kV` & enters the spacing between two parallel metallic plates
Correct Answer - `[0.05cm]`
2 Answers 4 views