The distance between the cathode (filament) and the target in an X-ray tube is 1.5 m. If the cutoff wavelength is 30 pm, find the electric field between the cathode and the target.
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An X ray tube with Copper target is found to emit characteristic X rays other than only due to Copper. The ka lie of Copper has a wavelength of `1.540
Correct Answer - `._(28)Ni`
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When the voltage applied to an X-ray tube increases from `10` to `20 kV` the wavelength difference between the ka line and the short wave cut-off of c
Correct Answer - `Cu (Z = 29)`
2 Answers 1 views
An X-ray tube has nickel as target. The wavelength difference between the ka X-ray and the cut-off wavelength of continuous X-ray spectrum is 84 pm. F
Correct Answer - `14.8 kV`
2 Answers 1 views
In a X-ray tube, after an electron has been removed from an inner shell of a target atom, an electron from outer shell falls into the vacancy and the
Correct Answer - `E_(k) - 2E_(L)`
2 Answers 1 views
The distance between the two plates of a cathode-ray oscilloscope is 1 cm and the potential difference between them is 1200 V. If an electron of energ
Correct Answer - [0.34 cm]
2 Answers 1 views
In a cathode ray tube a potential difference of `3000` volt is maintained between the electrodes `2 cm` apart. A magnetic field of `2.5xx10^(-4) Wb//m
Correct Answer - `1.8 xx 10^(11) C kg^(-1)`
2 Answers 1 views
In a cathode ray tube the length of deflection plates is `78 mm` and their separation is `0.24 m`, while the distance form the centre orf the plate to
Correct Answer - `1.59 xx 10^(11) C kg^(-1)`
2 Answers 1 views
What potential difference should be applied across an X-ray tube to get X-ray of wavelength not less than 0.10 nm? What is the maximum energy of a pho
Correct Answer - `[12.431 kV,1.99 xx10^(-15) J]`
2 Answers 1 views
Find the maximum potential difference which may be applied across an X-ray tube with tungsten target without emitting any characteristics K or L X-ray
Correct Answer - [Less than 11.3 kV]
2 Answers 1 views
An x-ray tube is operated at `20 kV` and the current through the tube is `0*5 mA`. Find (a) the number of electrons hitting the target per second, (b)
Correct Answer - `10`
2 Answers 1 views