Let G be the centroid of triangle ABC and the circumcircle of triangle AGC touches the side AB at A
If AC = 1, then the length of the median of triangle ABC through the vertex A is equal to
A. `(sqrt3)/(2)`
B. `(1)/(2)`
C. `(2)/(sqrt3)`
D. `(5)/(sqrt2)`


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Correct Answer - A
We have `AD = sqrt((2b^(2) + 2c^(2) -a^(2))/(4)) = (sqrt3b)/(2)`
If `b = 1 " then " AD = (sqrt3)/(2)`

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