Let G be the centroid of triangle ABC and the circumcircle of triangle AGC touches the side AB at A
If `angleGAC = (pi)/(3) and a = 3b`, then sin C is equal to
A. `(3)/(4)`
B. `(1)/(2)`
C. `(2)/(sqrt3)`
D. none of these
Correct Answer - B
In `DeltaADC`, we have,
`(a//2)/(sin (pi//3)) = (AD)/(sin C) rArr sin C = (sqrt3)/(2a) sqrt(2b^(2) + 2c^(2) -a^(2))`
`=(sqrt3)/(2a) sqrt(3b^(2)) = (3)/(2) (b)/(a) = (1)/(2)`
Given hyperbola is
`(x-1)(y-2)=5" (1)"`
and circle is
`(x-1)^(2)+(y+2)^(2)=r^(2)" (2)"`
These curves intersect at four points A, B, C and D.
We know curves intersect at four points is midpoint...
Correct Answer - B
Let the coordinates of D be `(alpha,beta)`. Then,
`(alpha+1+3)/(3)=3` or `alpha=5`
and `(beta+2+4)/(3)=2` or `beta=0`
`therefore D-=(5,0)`
Taking `A(x_1,y_1),B(x_1,y_1)`, and `C(x_3,y_3)`, we have
`(x_1+x_2)/(2)=1`,
`(x_2+x_3)/(2) =5, (x_3+x_1)/(2)=3`...
Correct Answer - b
A vector perpendicular to the plane of ` A(veca) , B(vecb) and C(vecc)` is
`(vecb -veca) xx (vecc-veca) = vecaxxvecb +vecb xx vecc +vecc xx veca`
Now...