A hydrogen atom at rest de-excites from n = 2 state to n = 1 state. Calculate the percentage error in calculation of momentum of photon if recoil of atom is not taken into account. The energy equivalent of rest mass of hydrogen atom is 940 MeV.
Correct Answer - C
(c) According to formula =, `E=(hc)/(lambda)(v=(c)/(lambda))`
Energy E=hv
`3.03xx10^(-19)=(hc)/(lambda)`
`lambda=(6.63xx10^(-34)xx3.0xx10^(8))/(3.03xx10^(-19))`
`=6.56xx10^(-7) m`
`=6.56xx10^(-7)xx10^(9)nm`
=`6.56xx10^(2) nm`
`=656 nm`