Absorption spectrum is obtained for a sample of gas having atomic hydrogen in ground state. Which lines of the spectrum will be in the range `94 nm` t

Correct Answer - B `E_(1) = (hc)/(lambda) [(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]` For second excited state to first excited state `E_(1) = (hc)/(lambda) [1/4 - 1/9] rArr (hc)/(lambda) ((5)/(36))` For first excited state...

Correct Answer - A::C::D `122.4 = (13.6Z^(2))/(1^(2)) rArr Z = 3, 91.8 = 122.4[1-(1)/(4)]` So an electron of KE `91.8 eV` can transfer its energy to this atom.

Correct Answer - A Room temperature `rArr n = 1` so lyman series

Correct Answer - C Shortest wave length of Lyman series of H-atom `1/lambda=1/x=R[1/((1)^(2))-1/((oo)^(2))]` So, `x=1/R` For Balmes series `1/lambda=R (1)^(2){1/((2)^(2))-1/((3)^(2))}` `1/lambda=1/x xx5/36` so, `lambda=(36 x)/(5)`

Correct Answer - 8 `(3)/(4)xx0.85ev=13.6xx1^(2)[(1)/(n^(2))-(1)/(y^(2))]" "thereforen=4,y=8`

Correct Answer - `Z = 3`

Correct Answer - An electron having `11 eV` kinetic energy.

Correct Answer - `20 eV, 13.2 eV`

Correct Answer - `[(a) 100nm, 560 nm, 3880 m; (b) 103nm, 121 nm, 654 nm]`

Correct Answer - 20.4 eV