Let `vecu,vecv,vecw` be such that `|vecu|=1,|vecv|=2,|vecw|3`. If the projection of `vecv along vecu` is equal to that of `vecw along vecv,vecw` are perpendicular to each other then `|vecu-vecv+vecw|` equals (A) 2 (B) `sqrt(7)` (C) `sqrt(14)` (D) `14`
A. 2
B. `sqrt7`
C. `sqrt14`
D. 14