Cards are drawn one-by-one at random from a well-shuffled pack of 52 playing cards until 2 aces are obtained from the first time. The probability that

Here, S={(1,2),(2,1),(1,3),(3,1),(2,3),(3,2),(1,4),(4,1),(1,5),(5,1),(2,4),(4,2),(2,5),(5,2),(3,4),(4,3),(3,5),(5,3),(5,4),(4,5)} `rArrn(S)=20` Let random variable variable be X which denotes the sum of the numbers on two cards drawn. X=3,4,5,6,7,8,9 At X=3,P(X)=`2/20=1/10` At X=4,P(X)`=2/10=1/10` At X =5,P(X)=`4/20=1/5` At X=6,...

Let `E_(1)`=Event for getting an even number on the die and `E_(2)`=Event that a spade card is selected `thereforeP(E_(1))=3/6=1/2andP(E_(2))=13/52=1/4` Then, `P(E_(1)capE_(2))=P(E_(1))cdotP(E_(2))=1/2cdot1/4=1/8`

Required probability=`4/52cdot4/52=1/13xx1/13`

Correct Answer - `({26!}^(4))/({13!}^(4)xx52!)` We have to find the probability that out of 26 cards drawn at random from the pack of cards, 13 will be red and 13 black. The...

Correct Answer - C If A draws card higher than B, then the number of favorable cases is (n - 1) + (n + 2) + … + 3 + 2...

Let events J be first drawn card is jack, Q be second drawn card is queen and K be third drawn card is king. We have to find the value...

Correct Answer - `11//50` Let `A_(1)` be the event that missing card is spade and `A_(2)` be event that missing card is non-spade. Then, `P(A_(1))=1/4,P(A_(2))=3/4` Let A be the event that...

Correct Answer - D A: exactly oen ace B: both aces E: `AuuB` `P(B//AuuB)=(""^(4)C_(2))/(""^(4)C_(1)""^(12)C_(1)+""^(4)C_(2))=6/54=1/9`

Correct Answer - B Let even A be drawing 9 cards which are not ace and B ve drawing an ace card. Therefore, the required probability is `P(AnnB)=P(A)xxP(B)` Now, there are...

Correct Answer - 4 Let event A:Card is of heart but not king (12 cards) Event B: King but not here (3 cards) Event C: Heart and king (1 card) `therefore`...