A binary number is made up to 8 digits. Suppose that the probability if an incorrect digit appearing is `p` and that the errors in different digits are independent of each other. Then find the probability of forming an incorrect number.


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Correct Answer - `1-(1-p)^(8)`
Probability for an incorrec digit is p. hence, probability for 8 correct digit is `1-p)^(8).` Hence, required probability is `1-(1-p)^(8).`

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