A three-digit number is selected at random from the set of all
three-digit numbers. The probability that the number selected has all the
three digits same is
`1//9`
b. `1//10`
c. `1//50`
d. `1//100`
A. `1//9`
B. `1//10`
C. `1//50`
D. `1//100`
Correct Answer - D
Three-digit numbers are 100, 101, …, 999. Total number of such numbers is 900. The three-digit numbers (which have all same digits) are 111, 222, 333, …, 999. Favorable number of cases is 9. Therefore, the probability is `9//900 = 1//100`.
Correct option is: A) \(\frac{3}{5}\)
There are 6 red, 3 black and 6 white balls.
\(\therefore\) Total number of balls = 6 + 3 + 6 = 15.
Number of balls which are not red =...
Correct option is (B) lies between 30 and 40
Let the two-digit number be ab where a is 10's digit and b is unit digit.
\(\therefore\) ab = 10a + b __________(1)
\(\because\) Sum of...
Correct Answer - `1-(1-p)^(8)`
Probability for an incorrec digit is p. hence, probability for 8 correct digit is `1-p)^(8).` Hence, required probability is `1-(1-p)^(8).`
Correct Answer - A
`S={00,01,02,....,49}`
Let A be the event that the sum of the digits on the selected ticket is 8. Then
`A={08,17,26,35,44}`
Let B be the event that the...
Correct Answer - C
`(c )` Case I : All six digits alike
i.e. `111111`, `222222`……..etc. `=5` ways
Case II : `2` alike `+2` other alike.
Select any three in `"^(5)C_(3)`...