Correct Answer - C
`AB=[(cos^(2) theta,),(cos theta sin theta,)][(cos^(2) phi,cos phi sin phi),(cos phi sin phi,sin^(2) phi)]`
`=[(cos^(2) theta cos^(2) phi+cos theta cos phi sin theta sin phi ,cos^(2)theta cos phi...
Correct Answer - B
`sin^(-1) x in [-(pi)/(2), (pi)/(2)]`
`cos^(-1) y in [0, pi]`
`sec^(-1) z in [0, (pi)/(2)) uu ((pi)/(2), pi]`
`rArr sin^(-1) x + cos^(-1) y + sec^(-1) z...