If 4 litre of `H_(2)` gas at 400 mm Hg and `47^(@)C` is transferred to 19 litre flask at `107^(@)C`. Then pressure of `H_(2)` gas is:
A. 191.7mm of Hg
B. 100 mm of Hg
C. 158.4 mm of Hg
D. 200 mm of Hg
1 Answers
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Two flask A and B have equla volumes.Flask A contains hydrogen at 600 K while flask B has same mass of `CH_4` at 300 K.Then choose the correct options
Correct Answer - A,C (i)molecule those have more `T/M` move faster so `H_2` move faster
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A one litre flask is full of reddish brown bromine fumes.The intensity of brown colour of vapour will not decrease appreciably on adding to the flask
Correct Answer - A Marble `(CaCO_(3))` do not react, adsorb, absorb, or dissolve `Br_(2)`.As such there is no change is colour of `Br_(2)`. Remaining dissolves or absorb or adsorb bromine.
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Calculate the pressure-volume work by the system when the gas expands from 1.0 litre to 2.0 litre against a constant external pressure of 10 atmospher
`-10` litre-atm, -242.2 cal, -1013.28J
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Work done in expansion of an ideal gas from `4` litre to `6` litre against a constant external pressure of `2.1 atm` was used to heat up `1` mole of w
`W-2.1[6-4]=-2.1xx2` `= -4.2 atmxxlit` `= -4.2xx101.325J` This work is used to heat up the water specific heat of `H_(2)O=4.2(J)/("gram".K)` Heat required for increasing temperature by `1^(@)C` of `1 "mole"=4.2xx18=75.6 J`...
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A gas expands against a variable pressure given by `P=(20)/(V)` bar. During expainsion from volume of `1` litre to `10` litre, the gas undergoes a cha
Correct Answer - 5 `Delta W=underset(1)overset(-10)intPdv= -20underset(1)overset(10)int(dv)/(V)=20[ l n(V)]_(1)^(10)= -20 ln(10)= -4605 J` `Delta q=Delta U-Delta w` `= 400-(-4605)=5005 J ~~ 5 KJ`
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`10` litre of a monoatomic ideal gas at `0^(@)C` and `10 atm` pressure is suddenly released to `1 atm` pressure and the gas expands adiabatically agai
Correct Answer - 64 L This is adiabatic irreversible process, so for this process `PV^(gamma)=` Constant, is not applicable `W= -P_(ext)(V_(2)-V_(1))` But for adiabatic process `W=dU=((P_(2)V_(2)-P_(1)V_(1))/(gamma-1))` `PV=nRT " "rArr10xx10=nxx0.082xx273rArrn=4.47` moles `-P_(ext)(V_(2)-V_(1))=((P_(2)V_(2)-P_(1)V_(1))/(gamma-1))...
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10 litre of `O_(2)` gas is reacted with 30 litre of CO gas at STP. Then volumes of each gas present at the end of reaction areL
Correct Answer - A `CO(g)+(1)/(2)O_(2)(g) to CO_(2)(g)` `{:(,t=0,30L,10L,0),(,"After reaction",(30-20)L,0,20L):}`
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The pressure of the gas was found to decrease from 720 to 480 mm. When 5g of sample of activated charcoal was kept in a flask of one litre capacity ma
Correct Answer - C `V_(2)=(P_(1)V_(1))/(P_(2))=(720xx1000)/(480)=1500 ml` Volume of gas in the flask `=1000- "volume of charcoal"=1000-5/1.25=996 ml` Total volume of gas adsorbe by charcoal `=1500-996=504 ml` Volume of gas adsorbe by...
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Two flask X and Y have volume 1 L and 2 L respectively and each of them contain 1mole of same ideal gas. The temperature of the flask are so adjusted
`PV=(1)/(3)MnU_("rms")^(2)` Since `(U_(avg))_(x)=2(U_(avg))_(y)` `P_(x)(I)=4xxP_(y)xx2` `P_(x)=8P_(y)`
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Two flask A and B of equal volume are taken. Flask a contains `(H_(2)(g)` at `27^(@)C` and 1 atm pressure. Flask B contain `N_(2)(g)` at `27^(@)C` and
(A) `KE_("avg")=(3)/(2)KT` (only depend on temperature) (B) `(n_(H_(2)))/(n_(N_(2)))=(1xxV)/(RT)xx(RT)/(2xxV)=(1)/(2)rArrn_(H_(2))=(n_(N_(2)))/(2)` (C ) `(W_(H_(2)))/(2)=(W_(N_(2)))/(28xx2)rArrW_(H_(2))=(W_(H_(2)))/(28) W_(H_(2))ltW_(N_(2))` (D) `(U_(rms)H_(2))/(U_(rms)N_(2))=sqrt(M_(N_(2))/(M_(H_(2))))=sqrt(14)gt1` `(U_(rms))_(H_(2))gt(U_(rms))N_(2)`
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