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A one litre flask is full of reddish brown bromine fumes.The intensity of brown colour of vapour will not decrease appreciably on adding to the flask

Monjur Alahi

A one litre flask is full of reddish brown bromine fumes.The intensity of brown colour of vapour will not decrease appreciably on adding to the flask some:
A. pieces of marble
B. animal charcoal powder
C. carbon tetrachloride
D. carbonisulphide


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Salim Ahmed Kawsar

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Correct Answer - A
Marble `(CaCO_(3))` do not react, adsorb, absorb, or dissolve `Br_(2)`.As such there is no change is colour of `Br_(2)`. Remaining dissolves or absorb or adsorb bromine.

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Which of the following compounds is not formed when a mixture of methyl bromine and ethyl bromine is treated with sodium metal in the presence of dry

Correct Answer - A Methane.

2 Answers 1 views
An amphoteric oxide dissolves in HCl to form a salt. The salt does not impart any colour to the flame and fumes in moist air. The oxide is

Correct Answer - C Be does not impart any colour to flame. Its oxide BeO is amphoteric in nature. With HCl it forms `Be_2.BeCl_2` fumes in moist air because of formation...

2 Answers 1 views
Two flask A and B have equla volumes.Flask A contains hydrogen at 600 K while flask B has same mass of `CH_4` at 300 K.Then choose the correct options

Correct Answer - A,C (i)molecule those have more `T/M` move faster so `H_2` move faster

2 Answers 1 views
When lead nitrate powder is heated in a boiling tube, we observe : (a) Brown fumes of nitrogen dioxide

Correct answer is (a) Brown fumes of nitrogen dioxide \(2 pb (NO_3)_2\) \(\overset{\text{heat}}{\longrightarrow}\) \(\underset{\text{Light yellow}}{2pbO↑} + \underset{\text{Reddish-Brown}}{4NO2↑}\) \(+ \underset{\text{colourless}}{O_2\uparrow}\) Hence, The brown fumes will be nitrogen dioxide.

2 Answers 1 views
A test tube containing a nitrate and another containing a bromide and `MnO_(2)` are treated with concentrated `H_(2)SO_(4)`.The reddish brown fumes ev

Correct Answer - B `NO_(3)^(-)` gives `NO_(2)` with concentrated `H_(2)SO_(4)` which on passing through water form colourless `HNO_(3)(l)` and `HNO_(2)(l)` `Br^(-)+MnO_(2)` on heating with concentrated `H_(2)SO_(4)` gives `Br_(2)` gas which on...

2 Answers 1 views
A reddish positive charged sol is obtained by adding small quantity of `FeCl_(3)` solution to freshly prepared and well washed `Fe(OH)_(3)` precipitat

It is due to adsorptions of `Fe^(3+)` ions on the surface of `Fe(OH)_(3)` which gives colloidal sol. `Fe(OH)_(3) ("ppt.")+Fe^(3+)("ions adsorbed") rarr [Fe(OH)_(3)]Fe^(3+)` ("colloidal sol.)

2 Answers 1 views
The pressure of the gas was found to decrease from 720 to 480 mm. When 5g of sample of activated charcoal was kept in a flask of one litre capacity ma

Correct Answer - C `V_(2)=(P_(1)V_(1))/(P_(2))=(720xx1000)/(480)=1500 ml` Volume of gas in the flask `=1000- "volume of charcoal"=1000-5/1.25=996 ml` Total volume of gas adsorbe by charcoal `=1500-996=504 ml` Volume of gas adsorbe by...

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If 4 litre of `H_(2)` gas at 400 mm Hg and `47^(@)C` is transferred to 19 litre flask at `107^(@)C`. Then pressure of `H_(2)` gas is:

`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))` `(400xx4)/(320)=(P_(2)xx19)/(180)rArrP_(2)=100mm` of Hg

2 Answers 1 views
Two flask A and B of equal volume are taken. Flask a contains `(H_(2)(g)` at `27^(@)C` and 1 atm pressure. Flask B contain `N_(2)(g)` at `27^(@)C` and

(A) `KE_("avg")=(3)/(2)KT` (only depend on temperature) (B) `(n_(H_(2)))/(n_(N_(2)))=(1xxV)/(RT)xx(RT)/(2xxV)=(1)/(2)rArrn_(H_(2))=(n_(N_(2)))/(2)` (C ) `(W_(H_(2)))/(2)=(W_(N_(2)))/(28xx2)rArrW_(H_(2))=(W_(H_(2)))/(28) W_(H_(2))ltW_(N_(2))` (D) `(U_(rms)H_(2))/(U_(rms)N_(2))=sqrt(M_(N_(2))/(M_(H_(2))))=sqrt(14)gt1` `(U_(rms))_(H_(2))gt(U_(rms))N_(2)`

2 Answers 1 views
Ina certain town, 40% of the people have brown hair, 25% have brown eyes, and 15% have both brown hair and brown eyes. If a person selected at random

Correct Answer - B We have, `P(A)=40/100,P(B)=25/100and P(AnnB)=15/100` So, `P((B)/(A))=(P(AnnB))/(P(A))=(15//100)/(40//100)=3/8`

2 Answers 1 views

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