Let `a = cos^(-1) cos 20, b = cos^(-1) cos 30 and c = sin^(-1) sin (a + b)` then
The largest integer x for which `sin^(-1) (sin x) ge |x -(a + b + c)|` is
A. 1
B. 2
C. 3
D. 4
Correct Answer - C
`a = 20 - 6pi, b = 10 pi - 30, c = sin^(-1) sin(4pi - 10) = 10 - 3pi`
So, `a + b + c = pi`
`sin^(-1) sin x ge |x -pi| rArr x in [(pi)/(2), pi]`
So, largest integer x = 3
By defing A & B are equal if they have the same order and all the corresponding elements are equal.
Thus we have `sin theta=(1)/(sqrt2),c os theta=-(1)/(sqrt2)& tan theta=-1`
`Rightarrow...
Correct Answer - C
`AB=[(cos^(2) theta,),(cos theta sin theta,)][(cos^(2) phi,cos phi sin phi),(cos phi sin phi,sin^(2) phi)]`
`=[(cos^(2) theta cos^(2) phi+cos theta cos phi sin theta sin phi ,cos^(2)theta cos phi...