Abhinav obtained 65 and 80 marks in first two unit test .Find the minimum marks he should get in the third test of have an average of at least 70 mark

Correct Answer - A `[F] = MLT^(-2)` In new system `1 "unit force" = ((1 "unit mass") (1 "unit length"))/((1 "unit time")^(2))` `= ((4 kg)(3m))/((2 sec)^(2)) = 3 N`

`l_(1) + epsilon = (V)/(4f_(0)) l_(2) + epsilon = (3V)/(4f_(0))` solve both equations and get `epsilon = 1cm` for third resonance `l_(3) + epsilon = (5V)/(4f_(0)) get l_(3) = 124cm`...

Correct Answer - B Total students =100 Total marks of 70 students is `75xx70=5250`. Total marks of girls is 7200-5250=1950 So average of girls is `(1950)/(30)=65`

From second equation of motion i.e. `h=(1)/(2)"gt"^(2)(h=ut+(1)/(2)"gt"^(2)` and u=0) `h_(1):h_(2):h_(3)......=(1)/(2)g(1)^(2):(1)/(2)g(2)^(2):(1)/(2)g(3)^(2)=1^(2):2^(2):3^(2)......=1:4:9....` Now from the of distance travelled in `n^(th)` second `S_(n)=u+(1)/(2)a(2n01)` here u=0, a=g `S_(n)=(1)/(2)g(2n-1)` or `S_(1):S_(2):S_(3):......=(1)/(2)g(2xx1-1):(1)/(2)g(2xx2-1):(1)/(2)g(2xx3-1)=1:3:5.....`

`theta_(1)=(2pi)/(3)and theta_(2)=(2pi)/(3)"total time T"=2+1=3s therefore ltomega_(av)gt(theta_(1)+theta_(2))/(T)=((2pi)/(3)+(2pi)/(3))/(3)=((4pi)/(3))/(3)=(4pi)/(9)"rad/s"`

`[E]=[ML^(2)T^(-2)]=(5)` `=(10)^(2)(5)^(2)=20` joules

Step 1: Open LibreOffice Calc and add fields like Name, Math, Physics, Chemistry, Biology, Total, Percentage. Step 2: Enter 10 records in it. Step 3: To Calculate Total Click inside the cell where...

If a coin is tossed three times, then the sample S is `S={HHH,HHT, HTH, HT T ,THH,THT, T TH, T T T }` `thereforen(S)=8.` (i) `A={HHH, HTH, THH, T TH]`...

Range = highest value - lowest value = 95-33 = 62 marks Quartile Deviation (Q) ` Q_(1) = 54.25` `Q_(3) = 86.25` `Q = (Q_(3) - Q_(1))/(2) = (86.25 -...

Correct Answer - `198,33%`