Correct option is (D) 16 : 81 Given that sides of two similar triangles are in the ratio of 4:9. i.e., \(\frac{S_1}{S_2}=\frac49\) We know that the ratio of areas of two similar triangle is square of the...
2 Answers 1 viewsLet the points on the circle be `A_(1), A_(2), A_(3), A_(4), A_(5)` and `A_(6)` in order. Since two triangles are drawn with no vertex common and none of the sides...
2 Answers 3 viewsCorrect Answer - 1 `9x^(2)-24xy+16y^(2)-12x+16y-12=0` or `(3x-4y+2)(3x-4y-6)=0` Hence , the distance between the lines is `(|6-(-2)|)/(5)=(8)/(5)`.
2 Answers 1 views⇒ Perimeter of triangles is 27cm. ⇒ Sides are given in ratio 3:2:4 ⇒ We know, Perimeter of triangle = Sum of all sides. ⇒ Let sides of triangle are 3x,2x and 4x. ⇒...
2 Answers 1 viewsAs discussed earlier, three medians of a triangle divide the triangle into six equal areas. So point R must be centroid. Therefore, `R-=((3+6+0)/(3),(4+0+0)/(3))-=(3,(4)/(3))`
2 Answers 1 viewsCorrect Answer - `120^(@)` Let the sides be `x - d, x, x + d`. Then `s = (3x)/(2), (s -a) = (x)/(2) + d`, `(s-b) = (x)/(2), (s-c) = (x)/(2)...
2 Answers 1 viewsCorrect Answer - A Given that `4A + A + A = 180^(@)` or `A = 30^(@)` Angle are `120^(@), 30^(@), 30^(@)` `rArr (sin 120^(@))/(a) - (sin 30^(@))/(b) = (sin 30^(@))/(c)...
2 Answers 1 viewsCorrect Answer - A Given `r_(1), r_(2), r_(3)` are in H.P. Thus, a, b, c are in A.P and `a + b + c = 24 = 2s` or `ab +...
2 Answers 1 viewsCorrect Answer - B Let a, b and `c(a lt b ltc)` be the sides of given triangle. Also, `2r = a + b - c` ltbr when `r = 4`...
2 Answers 3 views