One mole of an ideal monoatomic gas `(gamma = (5)/(3))` is mixed with one mole of a diatomic gas `(gamma=(7)/(5))`. (`gamma` denotes the ratio of specific heat at constant pressure, to that at constant volume) find `gamma` for the mixture?
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0.5 mole of an ideal monoatomic gas at STP conditions undergoes a process , if the final volume of gas is `(22.5xxe)` lit, then the entropy change in
`(V_(1))/(V_(2))= (T_(1))/(T_(2)) rArr (22.7//2)/(22.7. e)= (273)/(T_(2))rArr" " T_(2) = 273.(2e)` `DeltaS = nC_(p)lm.(T_(2))/(T_(1))" "0.5 xx (5)/(2)R xx ln. ((273).(2e))/((273))` `= (5)/(4) R(ln 2e) =(5)/(4) R(ln 2 + ln e)" "thereforeif...
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One mole of an ideal monoatomic gas expanded irreversibly in two stage expansion . `"State"-1" "("8.0 bar, 4.0 liters, 300K")` `"State"-2" "("2.0 bar,
Correct Answer - C `W = - P_(ext)[V_(2)-V_(1)]` `W_(1) = - 2 [16-4] xx 100 " "= - 2400 J` `W_(2) = - [32 -16] = - 16 xx 100 =...
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One mole of an ideal monoatomic gas `(C_(V.M)= 1.5 R)` is subjected to the following sequence of steps : (a) The gas is heated reversibly at constant
Correct Answer - (a) `q= DeltaH = 1558.88, DeltaU = 935.33 ; W= - P(DeltaU) = - 623.55 J mol^(-1)` (b) `W =- 2149.7 J//mol ; DeltaU & DeltaH =...
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`5`n , n and `5`n moles of a monoatomic , diatomic and non-linear polyatomic gases (which do not react chemically with each other ) are mixed at room
Correct Answer - D `f_(eq) = (f_(1)n_(1) + f_(2)n_(2) + f_(3)n_(3))/(n_(1) + n_(2)+ n_(3)) = ((5n) (3)(n)(5)+(5n)(6))/(5n + n+ 5n) = (50)/(11)`
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A mixture of `n_(1)` moles of monoatomic gas and `n_(2)` moles of diatomic gas has `(C_(p))/(C_(V))=gamma=1.5`
Correct Answer - A ` gamma = (n_(1)C_(P1) + n_(2)C_(P2))/ (n_(1)C_(V1) + n_(2)C_(V2))` ` gamma = 1.5 therefore C_(P1) = (5R)/(2) , C_(P2) = (7R)/(2) ` ` C_(V1) = (3R)/(2) ,...
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Molar heat capacity of an ideal gas in the process `PV^(x)` = constant , is given by : `C = (R)/(gamma-1) + (R)/(1-x)`. An ideal diatomic gas with `C_
Correct Answer - A `P alpha V implies PV^(-1) = "constant" implies x = -1` `implies C = C_(V) +(R)/(2) = (5R)/(2) + (R)/(2) = 3R`
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One mole of ideal monoatomic gas `(gamma=5//3)` is mixed with one mole of diatomic gas `(gamma=7//5)`. What is `gamma` for the mixture? `gamma` Denote
Correct Answer - B Monoatomic `" "` `n_(1) = 1` Diatomic `n_(2) = 1 gamma_(2) = (7)/(5)` `(n_(1) + n_(2))/(gamma_("mix") - 1) = (n_(1))/(gamma_(1) - 1) + (n_(2))/(gamma_(2) - 1) implies...
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One mole of an ideal monoatomic gas is caused to go through the cycle shown in figure. Then, the change in the internal energy is expanding the gas fr
Correct Answer - D `Pv= nRT` at point `C` `2P_(0)xx4V_(0)=1xxRT_(c)` `T_(c )=[(8P_(0)V_(0))/(R )]` at point a `P_(0)V_(0)=1xxRT_(0)` `T_(0)=(P_(0)V_(0))/(R ) , T_(c )=8T_(0)` change in internal energy `=[ nC_(v)dT]` For path `a`...
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`1` mole of an ideal diatomic gas undergoes a reversible polytropic process `(PV^(2)="constant")`. The gas expand from initial volume of `1` litre and
Correct Answer - B For polydropic process `(n=2)` `PV^(2)=C` `TV=C` `T_(1)V_(1)=T_(2)V_(2)` `300xx1=T_(2)xx3 rArrT_(2)=100 K` ` Delta U=nC_(v,m)Delta T=1xx(fR)/(2)(T_(2)-T_(1))=1xx(5xxR)/(2)xx(100-300)=(1xx5xxR)/(2)xx200= -500 R= -4.2 KJ`
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One mole of an ideal monoatomic gas at temperature `T` and volume `1L` expands to `2L` against a constant external pressure of one atm under adiabatic
Correct Answer - B `Delta U=W` `nCV(T_(2)-T)= -Pxx(V_(2)-V_(1))` `(3)/(2)R(T_(2)-T)= -1 " " :. T_(2)=T-(2)/(3xx0.0821)`
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