A train moves in north direction with a speed of 54 km/hr. and a monkey running on the roof of the train, against its motion with a velocity of 18km/hr. with respect to the train, then the velocity of monkey as observed by a man standing on the ground:-
A. `5 ms^(-1)` due south
B. `25 ms^(-1)` due south
C. `10 ms^(-1)` due south
D. `10 ms^(-1)` due north


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Correct Answer - D
`vecV_(TG)=54xx(5)/(18)=15m//s=15hatj`
`vecV_(MT)=-18xx(5)/(18)=-5m//s=-5hatj`
`vecV_(MT)=vecV_(MG-vecV_(TG)`
`vecV_(MG)=vecV_(MT)+vecV_(TG)=-5hatj+15hatj`
`=10hatj=10m//s` along north

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