Replication of DNA occurs
(A) 3’ → 5’ direction
(B) 5’ → 3’ direction
(C) Both 3’ → 5’ and 5’ → 3’ direction
(D) None of these
Correct Answer - A Stalled forks activate checkpoint signaling and pause replication. Since, ` G_(1)`/ S checkpoint checks DNA damage, cells size prior to S-phase (i.e. DNA replication phase), this checkpoint...
2 Answers 1 viewsCorrect Answer - A The events for initiation of DNA replication in prokaryotes may be classfied into (a) pre- priming (occurring only at the origin), (b) priming (recurring with the initiation...
2 Answers 1 viewsCorrect Answer - B Since , each daughter DNA molecules contains one strand of the parent DNA double helix (only one strand synthesised afresh) the process of replication is called semi...
2 Answers 1 viewsIn DNA AGCT is associated with pair ATGC because in a DNA molecule , the purine adenine in either chain is associated with the pyrimidine thymidine on the other ....
2 Answers 1 views(a) Replication and Transcription. (b) If both the stands take part in trenscription. `**" "`one segment of DNA would be coding for two different proteins which will complicate the genetic...
2 Answers 1 viewsCorrect Answer - B We have `T_(r+1)=.^(29)C_(r)3^(29-r)(7x)^(r)=(.^(29)C_(r)xx3^(29-r)xx7^(r))x^(r)` Coefficient of `(r+1)^(th)` term is `.^(29)C_(r) xx 3^(29-r)xx7^(r )` and coefficient of `r^(th)` term is `.^(29)C_(r-1)xx3^(30-r) xx 7^(r-1)` From given condition `.^(29)C_(r) xx 3^(29-r)...
2 Answers 1 viewsCorrect Answer - `n=14` According to question `""^(n)C_(6)((1)/(2))^(6)((1)/(2))^(n-6)=""^(n)C_(8)((1)/(2))^(8)((1)/(2))^(n-8)` `or ""^(n)C_(6)((1)/(2))^(n)=""^(n)C_(8)((1)/(2))^(n)` `or""^(n)C_(6)=""^(n)C_(8)=""^(n)C_(n-8)` `implies6=n-8orn=14`
2 Answers 1 viewsCorrect Answer - B Consider the following events: A: Father has at least one boy B: Father has 2 boys and one girl Then, A= one boy and 2 girls, 2...
2 Answers 1 viewsCorrect Answer - C The required probability is `=[""^(4)C_(0)((1)/(2))^(0)((1)/(2))^(4)]^(2)+[""^(4)C_(1)((1)/(2))^(1)((1)/(2))^(3)]^(2)` `=[""^(4)C_(2)((1)/(2))^(2)((1)/(2))^(2)]^(2)+[""^(4)C_(3)((1)/(2))^(3)((1)/(2))^(1)]^(2)` `+[""^(4)C_(4)((1)/(2))^(4)((1)/(2))^(0)]^(2)=35/128`
2 Answers 1 viewsCorrect Answer - A::D Let `P(E)=eand P(F)=f` `P(EuuF)-P(EnnF)=11/25` `impliese+f-2ef=11/25" "(1)` `P(barEnnbarF)=2/25` `implies(1-e)(1-f)=2/25" "(2)` From (1) and (2), `ef=12/25and e+f=7/5` Solving, we get `e=4/5,f=3/5or e=3/5,f=4/5`
2 Answers 1 views