A plant was found growing on other plant. Teacher said it is not a parasite. It exhibited two types of roots.

Monjur Alahi

A plant was found growing on other plant. Teacher said it is not a parasite. It exhibited two types of roots.


0 like 0 dislike
1 views
Share with your friends

1 Answers

Salim Ahmed Kawsar

Call

a. Student must have observed an epiphytic plants like Dendrobium, Vanda growing on other plant. 

b. The two types of roots exhibited by this plant must be clinging roots and epiphytic roots. 

c. Clinging roots: 

1. Clinging roots are tiny roots develop along intemodes, show disc at tips. 

2. It exudes sticky substance which enables plant to get attached to the substratum without damaging it. 

d. Epiphytic roots: 

1. Epiphytic plants like Vanda, Dendrobium grow on branches of trees in dense rain forests and are unable to obtain moisture from soil.

2. Such plants produce epiphytic roots which hang in the air. 

3. The roots are provided with a spongy membranous absorbent covering of the velamen tissue. 

4. The cells of velamen tissue are hygroscopic and have porous walls, thus they can absorb moisture from air. 

5. Epiphytic roots can be silvery white or green and are without root cap.

0 like 0 dislike
1 views
Talk Doctor Online in Bissoy App
Riya found a peculiar plant on her visit to Himachal Pradesh. What are the ways she can show it to her biology teacher

1. Riya can press and mount the plant specimen on a herbarium sheet and preserve the dried plant material, until she returns back from her visit.  2. She can also write...

2 Answers 1 views
Gita said that the probability of impossible event is 1. Pravallika said that probability of sure event is 0 and Atiya said that the probability

Correct option is: C) Atiya \(\because\) Probability of an impossible event is 0 \(\neq\) 1. Hence, the statement of Gita is wrong. Also, probability of a sure event is 1 \(\neq\) 0 Hence, the statement of Pravallika is wrong. Since, 0 \(\leq\) P \(\leq\) 1,...

2 Answers 1 views
Gita said that the probability of impossible event is 1. Pravallika said that probability of sure event is 0 and Atiya said that the probability 2 Answers 1 views
Cnidarians and Ctenophorans are both diploblastic. Which other character do they have in common, which is not found in other phyla?

Cnidarians and ctenophorans show tissue level of body organization. They have blind sac body plan and radially symmetrical body.

2 Answers 1 views
Students were observing a film on Paramoecium. It underwent a process of reproduction. Teacher said it is due to cell division.

1. Paramoecium is a unicellular organism. The division in Paramoecium occurs by amitosis.  2. It is the simplest mode of cell division.  3. In amitosis, nucleus elongates and a constriction appears. This...

2 Answers 1 views
While observing a section, many scattered vascular bundles could be seen. Teacher said, in spite of this large number

1. Students must have observed monocot stems.  2. It is because, monocot stem shows scattered vascular bundles.  3. In monocot stem, vascular bundles are closed i.e. without cambium.  4. Thus, secondary growth does...

2 Answers 1 views
There were two cut logs of wood lying in the campus. One had growth rings and other didn’t. Teacher said it is due to differences

1. It is possible that one of the cut logs was of a tropical tree, whereas the other was of a temperate tree. Since tropical trees grow in a similar...

2 Answers 16 views
Many plants in the marshy region had upwardly growing roots. They could be better seen during low tide.

a. Plants growing in marshy region (halophytes) produce upwardly growing roots called as pneumatophores or respiratory roots.  b. The main root system of these plants does not get sufficient air for...

2 Answers 2 views
A cell at telophase stage is observed by a student in a plant brought from the field. He tells his teacher that this cell is not like other cells at t

Correct Answer - A Polyploid cells have a chromosome number that is more than double the haploid number, e.g. Triticum aestivum (wheat) is a hexaploid (6n).

2 Answers 1 views
Consider quadratic equations `x^2-ax+b=0 and x^2+px+q=0` If the above equations have one common root and the other roots are reciprocals of each other

Correct Answer - A `(a)` x^(2)-ax+b=0`……..`(i)` x^(2)-px+q=0`……….`(ii)` Let the roots of `(i)` be `alpha`, `beta` and that of `(ii)` be `alpha`, `(1)/(beta)` `:. Alpha+beta=a`, `alphabeta=b`, `alpha+(1)/(beta)=p`, `(alpha)/(beta)=q` `:.((q-b)^(2))/((p-a)^(2))=(alpha^(2)((1)/(beta)-beta)^(2))/(((1)/(beta)-beta)^(2))` But `alpha^(2)=alphabeta*(alpha)/(beta)=bq` `implies...

2 Answers 1 views
X