When an `alpha` particle of mass m moving with velocity v bombards on a heavy nucleus of charge Ze, its distance of closest approach form the nucleus depends on m as
A. `(1)/(sqrt(m))`
B. `(1)/(m^(2))`
C. m
D. `(1)/(m)`


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Correct Answer - D
When an `alpha` particle of the mass m moving with velocity v bombards on a heavy nucleus of charge Ze, then there will be no less of energy , so intial kinetic energy of `alpha` particle at closet apporach.
`rArr" " (1)/(2)mv^(2)=(2Ze^(2))/(4piepsi_(0)r_(0))rArrr_(0)prop(1)/(m)`

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