If an electron has spin quantum number value is `+ (1)/(2)` and magnetic quantum number value is `-1`, then it cannot be present in
A. f-orbital
B. d-orbital
C. p-orbital
D. s-orbital
Correct Answer - D Torque, `"Torque", vec(tau)=vec(m)xxvec(B)=mB sin theta` and magnetic potential energy `U_(m)=vec(m).vec(B)=mB sin theta` `theta=0^(@)` the dipole will be in most stable position `pi=mB sin theta=mB sin 0^(@)=0` `and...
2 Answers 1 viewsCorrect Answer - D `CH_3-undersetOunderset"||"C-H underset((ii)H^(o+)) overset((i)NaOH + HCN) to (A) underset"Hydrolysis" overset"Partial"to (B)`
2 Answers 1 viewsHere, `T=("Number of revolutions")/("Time taken")=(5)/(10)=0.5s` `" " M=7.2Am^(2),I=6.5xx10^(-6)kgm^(2)` `As, " " T=2pi sqrt((I)/(MB)) or T^(2)=4pi^(2)(I)/(MB)` The magnetude of the magnetic field is `" " B=(4pir^(2)I)/(MT^(2))=(4xx(3.14)^(2)xx6.5xx10^(-6))/(7.2xx(0.5)^(2))=1.42xx10^(-4)T`
2 Answers 20 viewsCorrect Answer - B `{:(s = 1,t = 0,u = - (1)/(2)","(1)/(2),),(s = 2,t = 0,u = - (1)/(2)","(1)/(2),),(,t = 3,u = - 2"," -1"," 0","+1","+2 ,),(s = 3,t = 0,u...
2 Answers 1 viewsCorrect Answer - B S=1 t=0 `u=-1/2,1/2` No of subshell=1 , No of orbital=2 No of electrons =8 S=2 t=0,3 `u=-1/2,1/2`(for t=0) u=-2,-1,0,+1,+2(for t=3) No of subshell=2, No of orbital=7 No...
2 Answers 1 viewsCorrect Answer - C S=1 t=0 `u=-1/2,1/2` No of subshell=1 , No of orbital=2 No of electrons =8 S=2 t=0,3 `u=-1/2,1/2`(for t=0) u=-2,-1,0,+1,+2(for t=3) No of subshell=2, No of orbital=7 No...
2 Answers 1 viewsCorrect Answer - D (d) Spatial orientation of the orbital with respect to standard set of cordinate axis. Magnetic quantum number -1 is possible only when the azimuthal quantum number have...
2 Answers 1 viewsCorrect Answer - (i) `+5//2` or `-5//2`, spin magnetic moment `=sqrt(35)` B.M. (ii) `0, 0` (i) `_(26)Fe^(3+): 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(5)` It contains `5` unpaired electrons `:. n=5` `:.` Total spin `= +-n/2= +-5/2`...
2 Answers 1 viewsCorrect Answer - C Total number of nodes = n - 1 = 4 - 1 = 3
2 Answers 1 viewsCorrect Answer - C x is `As rarr[Ar] 3d^(10)4s^(2)4p^(3)` `2|s|+1=4" "|s|=3//2` So, unpaired electron in electronic element x is 3.
2 Answers 2 views