The torque and magnetic potential energy of a magnetic dipole in most stable position ina uniform magnetic field `vec(B)` having magnetic moment `vec(m)` will be
A. `-mB,zero`
B. `mB,zero`
C. `zero,mB`
D. `zero,-mB`
Correct Answer - D
Torque, `"Torque", vec(tau)=vec(m)xxvec(B)=mB sin theta`
and magnetic potential energy `U_(m)=vec(m).vec(B)=mB sin theta`
`theta=0^(@)` the dipole will be in most stable position
`pi=mB sin theta=mB sin 0^(@)=0`
`and U_(m)=-mB cos theta=-mBcos 0^(@)=-mB`
Correct Answer - 1
`vecr.vecn=q`
Let , intercept made by the plane (1) on the x-axis is `x_(1)`
`implies` plane (1) passes through it
`x_(1),hati.vecn =q implies x_(1) =(q)/(hati.vecn)`
Correct Answer - C
Since the most stable position is at `theta=0` and the most unstable position is at `theta=180^(@)`, then the work done is given by
`w=underset(theta=0^(@))overset(theta=180^(@))inttau(theta)d theta=underset(theta=0^(@))overset(theta=180^(@))int mB sin...