An atom of the element A has 3 electrons in its outermost shell while another atom X has 6 electrons in its outermost shell. The formula of the compound between A and X could be
A. `A_2X_3`
B. `AX_3`
C. `A_3X_2`
D. `A_2X`
Correct Answer - C
Since the common oxidation state of metal is -2. This indictaes it is 2 electrons short of noble gas configuration. Therefore, it has six electrons in valence...
Correct Answer - D
`a=omega^(2)r`
As `" " omegaprop(1)/(n^(3))" " and " : r propn^(2)`
`" "aprop(1)/(n^(4))`
`rArr" " (a_(M))/(a_(L))=((2)/(3))^(4)=(16)/(81)`
Correct Answer - D
Helium has only two electrons in its valence shell. On the other hand all other noble gases have 8 electrons in their valence shell.