A spring of force constant k is cut into two pieces such that one piece such that one piece is double the length of the other. Then the long piece will have a force constant of
(A) (2/3)k
(B) (3/2)k
(C) 3k
(D) 6k
1 Answers
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A block of mass m is connected to another block of mass M by a spring (massless) of spring constant k.
(d) : Acceleration of the system a = F/(m + M) Force on block of mass m = ma = mF/(m + M).
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Two equal masses are attached to the two ends of a spring of spring constant k.
(d) -1/4kx2. Explanation:- The work done by the spring on both of the masses is equal to the potential energy stored in the spring. The potential energy stored in the spring =...
1 Answers 1 views
One end of a light spring of spring constant k is fixed to a wall and the other end is tied to a block placed on
(a) the spring was initially compressed by a distance! and was finally in its natural length (b) it was initially streched by a distance x and was in its natural length Explanation: Since in the...
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How many pieces of 8.6 metres length cloth can be cut out of a length of 455.8 metres cloth?
(d) Number of pieces = 455.8/8.6 = 53
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A wooden block of mass 0.5 kg and density 800 kg/m^3 is fastened to the free end of a vertical spring of spring constant 50 N/m
(a) The volume of wooden block = 0.5/800 m³ =0.000625 m³ The force of buoyancy =0.000625*1000 kg =0.625 kg The Net force on the block in the water =0.625-0.500 kg-weight =0.125*10 N {Taking g =...
1 Answers 1 views
Two equal masses are attached to the two ends of a spring of spring constant k,
(d) -1/4kx2. Explanation:- The work done by the spring on both of the masses is equal to the potential energy stored in the spring. The potential energy stored in the spring =...
1 Answers 1 views
One end of a light spring of spring constant k is fixed to a wall and the other end is tied to a block placed on a smooth horizontal surface.
(a) the spring was initially compressed by a distance! and was finally in its natural length (b) it was initially streched by a distance x and was in its natural length Explanation: Since...
1 Answers 1 views
A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49N,
(1) The reading of the spring balance is 24N. Explanation: When lift is stationary, W1 = mg When the lift descends with acceleration a, W2 = m(g – a) W2/W1 = (g – a)/g = (9.8 - 5)/9.8 = 4.8/9.8 W2 = W1 x (4.8/9.8) = 49 x (4.8/9.8) = 24 N
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A wire is cut into several small pieces. Each of the small pieces is bent into a square of side 2cm.
Original length of the wire = 56 cm.
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A mass of 2 kg is attached to the spring of spring constant 50 Nm^-1
Displacement at anytime t is x = 5 sin 5t.
1 Answers 1 views