Assertion (A).H2O2 has higher boiling point than water Reason (R). The dipole moment of H2O2 is little more than that of H2O.

This is because hydrogen bonding is multidimensional in water whereas in HF it is linear.

P = 3 x 10-8cm ; E =104N/C  At stable equilibrium (θ1 ) = 0°  At unstable equilibrium (θ2) =180°  Work done in rotating dipole is given by:  W = PE (cosθ1 - cosθ2 )   =...

Dipole moment P =5 x10-4Cm. Electric field (E) =104N/C At stable equilibrium θ1 = 0° At unstable equilibrium θ2 =180° Work done = - PE (cosθ2 - cosθ1) = -(5 x 10-8 ) (104 )...

Dipole moment of an electric dipole is the product of either of charge and the length of dipole. It is a vector quantity. vector P = q(2vector a)

Yes, the given statement is true .This is because at the same temperature, gaseous state is more disordered than the liquid state.

(b) If both (A) and (R)are true but (R) is not the true explanation of (A).

(D) If both assertion and reason are false.

c)1 cm3 of solution liberates 30 cm3 of O2 at STP

c) Prolonged electrolysis of water

(a) of relatively higher water content