There are 6 person ; A ,B, C, D, E and F. A has 3 items more than C
D has 4 items less than B
E has 6 items less than F
C has 2 items more than E
F has 3 items more than D
Which one of the following figure can not be equal to the total number of items possessed by all the 6 persons?
(a) 41 (b) 4 (c) 53 (d) 58
(c) A = C + 3, D = B – 4, E = F – 6
C = E + 2, F = D + 3
On adding, we get A = B – 2
Total number of items = A + B + C + D + E + F
=A + (A + 2) + (A – 3) + (A – 2) + (A – 5) + (A + 1)
= 6A – 7
If A= 8, Total number of items = 8 × 6 – 7 = 41
For A = 9, Total number of items = 9 × 6 – 7 = 47
For A = 10, Total number of items = 10 × 6 – 7 = 53