Green dyes =5
Blue dyes =4
Red dyes =3
The no of ways of choosing of at least one green and one blue is =(25−1)×(24−1)×23
⇒(32−1)×(16−1)×8
⇒31×15×8
⇒3720
Total combination of balls = 212
Combination of balls with no green balls = 27
Combination of balls with no blue balls = 28
Combination of balls with no blue balls and no green...
(a) According to the given statements, only statement 1 and 4 can both be true because there may be a situation, when all the balls are black (1) or it...