Given 5 different green dyes ,four different blue dyes and three different red dyes,the number of combinations of dyes which can be chosen taking at least one green and one blue dye is
Solution:
For an m×n chessboard there are 2m+2n−2 ways.
Case I. There are two horizontally adjacent squares of the same color: 2m−2 ways.
Case II. There are two vertically adjacent squares of the same color: 2n−2 ways.
Case III. None of the...
Solution: Total number of outcomes = 24
P (Green) = 2/3
If number of green balls is G then;
G/24 = 2/3
or, G = (24*2)/3 = 16
Hence, number of blue balls = 24 –...
On crossing red and white flower only red colour flower appeared in the F1 generation. But the white colour flower again appear in the F2 generation which is raised out...
Total combination of balls = 212
Combination of balls with no green balls = 27
Combination of balls with no blue balls = 28
Combination of balls with no blue balls and no green...