In a class there are 10 boys and 8 girls. The teacher wants to select a boy and a girl to represent the class in a function. In how many ways can the teacher make this selection?
The teacher has to perform two jobs :
(i) To select a boy among 10 boys, which can be done in 10 ways.
(ii) To select a girl, among 8 girls, which can be done in 8 ways.
Let the no. of girls be 5x
No. of boys=7x
According to the question
5x+8=7x
7x-5x=8
2x=8
x=8/2
x=4
No. of girls=5*4=20
no. of boys=7*4 or 5*4+8=28
Hence the total strength of the class is 20+28=48
False, because the outcomes are not actually, likely. For no girl, the outcome is bbb, for one girl, it is bgb, gbb, bbg, for two girls, it is bgg, ggb, gbg and...
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(d) Assume the 2 given students to be together (i.e one].
Now there are five students.
Possible ways of arranging them are = 5! = 120
Now, they (two girls) can arrange themselves...