Leaving one seat vacant between two boys may be seated in 4! ways. Then at remaining 5 seats, 5 girls any sit in 5! ways. Hence the required number = 4! × 5!
Let the no. of girls be 5x
No. of boys=7x
According to the question
5x+8=7x
7x-5x=8
2x=8
x=8/2
x=4
No. of girls=5*4=20
no. of boys=7*4 or 5*4+8=28
Hence the total strength of the class is 20+28=48
False, because the outcomes are not actually, likely. For no girl, the outcome is bbb, for one girl, it is bgb, gbb, bbg, for two girls, it is bgg, ggb, gbg and...
List of toys and games that boys play with: cars, guns, swords, buses, railway trains, lions, etc. (toys), cricket, kabaddi, hockey, football etc. (games). List of toys and games that...
10 persons can sit round a circular table in 9! ways. But here clockwise and anticlockwise orders will give the same neighbours. Hence the required number of ways =1/29 !
(d) Assume the 2 given students to be together (i.e one].
Now there are five students.
Possible ways of arranging them are = 5! = 120
Now, they (two girls) can arrange themselves...