When a metal wire elongates by hanging a load pn the gravitational potential energy is decreased.

Weight of an object on the moon = 1 / 6 × Weight of an object on the Earth  Also,  Weight = Mass × Acceleration  Acceleration due to gravity, g = 9.8 m/s2  Therefore,...

(c) B is correct but A is wrong. EXPLANATION:  (A) is not correct because the gravitational potential inside the shell is constant =-GM/a, where a is the radius of the shell. As...

(b ) ​U>K. EXPLANATION:  Let the mass of the moon = m, velocity v and its distance from the earth = a.   v = √(GM/a), K.E. = K = ½mv² = ½m*GM/a  →GMm/a = 2K  The...

All of these EXPLANATION:  Consider a thin spherical shell and choose r = infinity where potential is zero. At infinity V = 0, E = 0. So (a) is true. At any point outside...

The correct answer is (b) 1.0 mm Explanation:  The elongation will be the same because in both cases it is pulled by the same force at its both ends. In the case...

The correct answer is (a) ∆l/l Explanation:  When a metal wire is stretched by a load the fractional change in the transverse length is proportional to the fractional change in the longitudinal...

(d) None of these. Explanation:  When a mass is hanged by a wire the gravitational potential energy decreased is mgl (where l is the elongation) of the wire. But the elastic potential...

Length of wire  L= 3 m,  Load F = 10*10 N =100 N, {taking g = 10 m/s²}  Area of cross-section A = 4 mm²  →A = 4x10⁻⁶ m²  (a) The stress = Load...

(a) increases

(c) B is correct but A is wrong. EXPLANATION:  (A) is not correct because the gravitational potential inside the shell is constant =-GM/a, where a is the radius of the shell. As...