One end of a uniform rod of mass m and length I is clamped.

The correct answer is (a) T1 > T2. Explanation: Taking the rod of uniform mass per unit length = m . Mass beyond a distance r from the pivot = m(L-r). And this mass will be...

(c) 2mv2/r  must be acting on the system Explanation:  Since the heavy ring and the small particle have equal masses, the center of mass of the system will be at r/2 from the...

(d)1/2 mw2l. Explanation:  Since the rod rotates on the horizontal surface, the horizontal component of the force applied by the clamp is the centripetal force = mω²r = mω²(l/2) = ½mω²l.

(a) smallest at the top and gradually increases down the rod Explanation:  For a hanged heavy uniform rod, at any cross-section, the load is only of the part of the rod which...

(a) Since both types of wires are joined end to end, the same load will be on the cross-sections of them. If the load = F and the area of...

The correct answer is (b) 1/8(ωBl2).

(c) Both A and B are true

(b) The rod and the experimenter move with the same speed v in opposite directions.

The correct answer is (a) T1 > T2. Explanation: Taking the rod of uniform mass per unit length = m . Mass beyond a distance r from the pivot = m(L-r). And this mass...

(A) F1(1 -y/L)  Explanation: acceleration of string =F/M,  mass of portion of string between distance y and other end of string=M(1-y/L).  tension at distance y=M(1-y/L)F/M =F(1-y/L)